Algebra

69: 16x^2+8x-3. I inserted this into the quadratic formula and got -8+/- the square root of (8^2-4(16)(-3)/(2 times 16). This reduced to -8+/- the square root of (64+120)/32, which further reduced to -8+/-the square root of 184/32. I reduced the top part to -8 +/- the square root of four and the square root of six which became -8 +/- 2 times the square root of six over 32. I divided -8 and 32 by 8, resulting in -1 +/- the square root of six/-16. But my book said the answer is 1/4, -3/4. Where did I go wrong?

Thanks for your help!!!

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asked by Britt
  1. I got
    x = (-8 ± √(64 + 192)/32
    = (-8 ± √256)/32
    = (-8 ± 16)/32
    = 8/32 or -24/32
    = 1/4 or -3/4

    Can you find your error ?

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    posted by Reiny

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