Ap Physics

Water skiers often ride to one side of the center line of a boat, as shown in the figure . In this case, the ski boat is traveling at 15 (m/s} and the tension in the rope is 80 N.

If the boat does 3600 J of work on the skier in 51.3 m, what is the angle \theta between the tow rope and the center line of the boat?

Someone please help been trying for hours...

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  1. The component of the rope tension along the direction of motion is
    (Work)/(distance pulled) = 3600/51.3 = 70.2 N

    But you also know that
    70.2 = (rope tension)x cos theta

    sin theta = 0.877
    theta = 28.7 degrees

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