physic

A projectivle is launched with an initial speed of 40m/s at an angle of 35 degree above the horizontal. The projectitile lands on a hillside 4s later. negelct air friction.
a.What is the straight-line distance form where the prjectile was launched to where it hits its target?note that the hill may slope up or down from the launch point. Thank you

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asked by Chan
  1. Consider horizontal and vertical motions separately.

    Horizontal:
    velocity, v0 = 40*cos(35°) m/s
    Time, t = 4 s.
    Horizontal distance, H = v0*t m.

    Vertical:
    initial velocity, v0 = 40 sin(35°) m/s
    acceleration, a = -g m/s/s/
    Time, t = 4 s.
    vertical distance, V = v0*t+(1/2)at²

    Straignt line distance
    =√(H²+V²)

    Check my thinking and calculations.

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  2. pi

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    posted by blajj

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