Locate the discontinuities of the function.
y = ln(tan(x)2)

a)(pi)n, where n is any integer
b)(pi)/2 + ðn, where n is any integer
d)n(pi)/2, where n is any integer

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  1. a)(pi)n, where n is any integer
    b)(pi)/2 + (pi)n, where n is any integer
    d)n(pi)/2, where n is any integer

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  2. nevermind i got it

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  3. Is that supposed to be tan(x^2)? Or (tanx)^2? There is no such thing as a log of a negative number.

    There will be continuous regions where
    f(x) is not defined, in the first case. In the second case, the only discontinuity is were tanx is zero.

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