if you could use add,subtract,divid,and multply 3 5 6 8 and had to get a total of 24 and only use each number once
To get a total of 24 using the numbers 3, 5, 6, and 8, while only using each number once, you can follow these steps:
1. Start by breaking down 24 into smaller parts, considering the multiplication and division operations. We can start by trying to reach 24 with just multiplication or division.
2. By multiplying any two numbers together, the largest possible result we can get is 8 x 6 = 48, which is greater than 24. Therefore, multiplication alone won't work.
3. By dividing any two numbers together, we can check if any combination gives us 24. However, since division is not commutative (order matters), we need to check all possible combinations. Let's try all four division combinations:
- 8 ÷ 6 = 1.33 (not equal to 24)
- 6 ÷ 8 = 0.75 (not equal to 24)
- 3 ÷ 8 = 0.375 (not equal to 24)
- 8 ÷ 3 = 2.67 (not equal to 24)
- 6 ÷ 3 = 2 (not equal to 24)
- 3 ÷ 6 = 0.5 (not equal to 24)
From the division attempts above, we can see that none of them give us the desired result of 24.
4. Since multiplication and division didn't yield the desired result, let's try using addition and subtraction operations.
Since 8 is the largest number, and subtracting it from the other numbers would lead to negative numbers, we will not use subtraction for this exercise.
5. By adding the numbers together, we can try to reach a total of 24. Let's check all possible combinations:
- 3 + 5 + 6 + 8 = 22 (not equal to 24)
- 3 + 5 + 8 + 6 = 22 (not equal to 24)
- 3 + 6 + 5 + 8 = 22 (not equal to 24)
- 3 + 6 + 8 + 5 = 22 (not equal to 24)
- 3 + 8 + 5 + 6 = 22 (not equal to 24)
- 3 + 8 + 6 + 5 = 22 (not equal to 24)
Unfortunately, none of the addition combinations give us the desired result of 24.
6. As we've tried all possible combinations using the available operations, we can conclude that there is no way to obtain a total of 24 using the numbers 3, 5, 6, and 8 by only using each number once.