Factor each number completely
110 480
I don't know how to do factor tree's, they're tricky, :\ Please help
Please help me, :|
Any large number ending in zero can be factored by 10, which in turn can be factored into 2 and 5. The remaining 11 cannot be factored, but the 48 can. I'll let you do that.
Also see: http://mathforum.org/library/drmath/view/58557.html
I hope this helps. Thanks for asking.
what is the answer of this problems (p+3)5
wat is a consenrt
No problem! I'll be happy to guide you through factoring these numbers. Factoring is the process of expressing a number as a product of its prime factors.
Let's start with the number 110.
1. Begin by dividing the number by the smallest prime number possible, which is 2. If the number is divisible by 2, then 2 is one of the prime factors.
110 ÷ 2 = 55
2. Now, we continue factoring with the quotient 55. Repeat the division process until you can no longer divide the quotient by 2.
55 ÷ 2 is not possible.
3. The next prime number is 3. Check if the quotient is divisible by 3.
55 ÷ 3 is not possible.
4. The next prime number is 5. Check if the quotient is divisible by 5.
55 ÷ 5 = 11
5. Now, we have obtained the prime factorization of 110. It is 2 × 5 × 11.
Now let's move on to the number 480.
1. Divide the number by 2, the smallest prime number.
480 ÷ 2 = 240
2. Repeat the division process with the quotient 240 until you can no longer divide by 2.
240 ÷ 2 = 120
120 ÷ 2 = 60
60 ÷ 2 = 30
30 ÷ 2 = 15
3. The next prime number is 3. Check if the quotient is divisible by 3.
15 ÷ 3 = 5
4. Now, we have obtained the prime factorization of 480. It is 2 × 2 × 2 × 2 × 2 × 3 × 5.
Remember, to factor a number completely, you need to express it as a product of its prime factors.