Can you please tell me if I did this right? Or am I way off:
What are the odds in favor of getting at a head and a tail in a single toss of two coins?
HH
TT
HT
TH
2/4=1/2= 2:1
yes that is correct
Great! I finally get it! Thank you...
your very welcome Matt
To determine if you have calculated the probability correctly, let's walk through the steps of calculating the odds in favor of getting a head and a tail in a single toss of two coins.
Step 1: Determine the sample space - The sample space represents all possible outcomes. In this case, we have two coins, which can either result in a head (H) or a tail (T). So the sample space will have four possible outcomes: HH, HT, TH, and TT.
Step 2: Determine the favorable outcomes - The favorable outcomes are the ones that meet the specific condition mentioned, in this case, getting a head and a tail. From the sample space, we can see that only two outcomes meet this condition: HT and TH.
Step 3: Calculate the odds in favor - The odds in favor represents the ratio of favorable outcomes to unfavorable outcomes. In this case, since we only have favorable outcomes, the odds in favor of getting a head and a tail is simply the number of favorable outcomes (2) divided by the total number of outcomes (4):
Odds in favor = Favorable outcomes / Total outcomes = 2/4 = 1/2
Therefore, you are correct. The odds in favor of getting a head and a tail in a single toss of two coins are 1/2, which can also be expressed as a ratio of 2:1.