Cycle Paths, inc. makes bicycles, tricycles, and unicycles. Last week they made 88 more bicycles than unicycles, and 5 times as many tricycles as unicycles. If they made 40 more bicycles than tricycles, how many unicycles did they make?
Let summarize the data
B=number of bicycles made last week
T=number of tricycles
U=number of unicycles
B=88+U ....(1)
5U=T .....(2)
B=T+40 ....(3)
Put (2) in (3) to eliminate T
B=5U+40 ....(4)
Equate (1) and (4) to eliminate B
5U+40 = 88 + U
4U = 48
U = 12
Substitute U in (2)
T = 5*12 = 60
and in (1)
B = 88 + 12 = 100
So Cycle Paths made 12 Unicycles, 60 tricycles and 100 bicycles.
Please check these numbers against the original question.
To solve this problem, let's start by assigning variables to the unknowns:
Let's say the number of unicycles made is 'x'.
Given that Cycle Paths, inc. made 88 more bicycles than unicycles, the number of bicycles made will be 'x + 88'.
Also, it is mentioned that they produced 5 times as many tricycles as unicycles, so the number of tricycles made will be '5x'.
Now, according to the given information, the number of bicycles made was 40 more than the number of tricycles made.
So we can set up the equation:
x + 88 = 5x + 40
Next, we can solve this equation to find the value of 'x'. We will gather all the similar terms on one side and isolate the variable:
Subtract 'x' from both sides:
88 = 4x + 40
Next, subtract 40 from both sides:
88 - 40 = 4x
48 = 4x
Finally, divide both sides by 4:
48/4 = 4x/4
12 = x
Therefore, Cycle Paths, inc. made 12 unicycles.