If your MP100 (random name for the ECG device) is recording at 10 sps (samples per second) and your input analog signal is at 100Hz, how many waves would the data acquisition miss in a 5 s recording?

can someone tell me how this is calculated?

i have the same name as me

I am wondering the same thing

To calculate the number of waves missed in a 5-second recording given an ECG device recording at 10 samples per second (sps) and an input analog signal frequency of 100Hz, we need to consider the sampling rate and the Nyquist-Shannon sampling theorem.

The Nyquist-Shannon sampling theorem states that in order to accurately represent a signal, the sampling rate must be at least twice the frequency of the signal being sampled. This is known as the Nyquist rate.

In this case, the Nyquist rate would be 2 times the input signal frequency, which is 100Hz. So the Nyquist rate would be 200 samples per second.

Now, if the ECG device is recording at 10 sps, it means it is sampling the signal 10 times per second.

To calculate the number of waves missed, we can find the ratio between the Nyquist rate and the sampling rate:
Missed Waves = Nyquist rate / Sampling rate.

Missed Waves = 200 sps / 10 sps = 20 waves.

Therefore, in a 5-second recording with these specifications, the data acquisition would miss 20 waves of the input analog signal.