What amount of H2(g) is produced when 12g of magnesium reacts completely with dilute HCl(aq)
Mg(s) + 2HCl(aq)________MgCl2(aq) + H2(G)
The arrow is after 2HCL and giving the following. MgCl2(aq) + H2 (g)
To find the amount of H2(g) produced when 12g of magnesium reacts completely with dilute HCl(aq), you need to use stoichiometry and the concept of mole ratio.
First, you need to determine the balanced chemical equation for the reaction:
Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
From the balanced equation, you can see that 1 mole of magnesium (Mg) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of hydrogen gas (H2).
1. Calculate the molar mass of magnesium (Mg):
- Molar mass of Mg = atomic mass of Mg = 24.31 g/mol
2. Use the molar mass of magnesium to convert the given mass of 12g into moles:
- Moles of Mg = 12g / (24.31 g/mol) = 0.493 moles of Mg
3. Apply the mole ratio from the balanced equation to determine the moles of hydrogen gas (H2) produced:
- According to the balanced equation, 1 mole of Mg reacts to produce 1 mole of H2.
- Therefore, the moles of H2 produced = 0.493 moles of Mg
4. Finally, calculate the mass of H2(g) produced using the molar mass of hydrogen (H2):
- Molar mass of H2 = 2.016 g/mol
- Mass of H2(g) produced = Moles of H2 × (Molar mass of H2)
- Mass of H2(g) produced = 0.493 moles × (2.016 g/mol) = 0.992 g
So, when 12g of magnesium reacts completely with dilute HCl(aq), approximately 0.992 grams of hydrogen gas (H2) will be produced.
You can make an arrow one of two ways. ==> or ---->.
When you say "amount of hydrogen" is that amount by volume or amount by mass. I will assume you mean mass.
Convert 12 g Mg to moles. moles = grams/atomic mass.
Using the coefficients in the balanced equation, convert moles Mg to moles hydrogen.
Convert moles hydrogen to grams using grams = moles x molar mass.
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What amount of H2(g) is produced when 12g of magnesium reacts completely with dilute HCl(aq)
Mg(s) + 2HCl(aq) ------> MgCl2(aq) + H2(g)