Lithium hydroxide reacts with carbon dioxide as follow.
2LiOH + CO2________ Li2CO3 + H2O
What mass (in grams) of Lithium hydroxide is need to react with 11 g of carbon dioxide?
Richard, Ochaya, Mary, or whomever. It helps us if you don't change names and you don't get any faster answers by us; in fact it may take us longer since we follow up on old posts before taking new ones. This problem is worked the same way as the other two I've shown you how to work (FeS2 problem and hydrogen problem). Post your work if you get stuck.
What, what?
Mary, Richard, and Ochaya posted similar questions, similarly quoted, and using the same kind of type, all withing a few posts of each other, and on the same computer. Many students change names because they think we won't answer if the same student posts too many questions but that isn't true. Here is a link to one of the posts that is quite similar to your with details about how to work it. Post your work if you have any trouble and we can help you through.
http://www.jiskha.com/display.cgi?id=1254155172
To determine the mass of lithium hydroxide needed, we can use the balanced chemical equation and molar ratios.
From the balanced equation, we know that 2 moles of LiOH react with 1 mole of CO2. Therefore, we need to convert 11 g of CO2 to moles, then use the molar ratio to find the moles of LiOH required, and finally convert the moles of LiOH to grams.
The molar mass of CO2 is 44.01 g/mol, and the molar mass of LiOH is 23.95 g/mol.
Step 1: Calculate the moles of CO2 using the given mass and molar mass:
moles of CO2 = mass of CO2 / molar mass of CO2
= 11 g / 44.01 g/mol
= 0.25 mol
Step 2: Use the molar ratio to determine the moles of LiOH required:
moles of LiOH = 2 * moles of CO2
= 2 * 0.25 mol
= 0.5 mol
Step 3: Convert the moles of LiOH to grams using the molar mass of LiOH:
mass of LiOH = moles of LiOH * molar mass of LiOH
= 0.5 mol * 23.95 g/mol
= 11.98 g
Therefore, you would need approximately 11.98 grams of lithium hydroxide to react with 11 grams of carbon dioxide.
To determine the mass of lithium hydroxide needed to react with 11 grams of carbon dioxide, we need to use the given balanced chemical equation:
2LiOH + CO2 -> Li2CO3 + H2O
From the equation, we can see that the ratio of lithium hydroxide to carbon dioxide is 2:1. This means that for every 2 moles of lithium hydroxide, we need 1 mole of carbon dioxide.
To start, we need to convert the mass of carbon dioxide (11 g) to moles. We can do this by dividing the given mass by the molar mass of carbon dioxide.
The molar mass of carbon dioxide (CO2) is calculated by adding the atomic masses of the elements present. The atomic mass of carbon (C) is approximately 12.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol. Since carbon dioxide has one carbon atom and two oxygen atoms, the molar mass is:
(12.01 g/mol) + 2(16.00 g/mol) = 44.01 g/mol
Now, we can calculate the number of moles of carbon dioxide by dividing the given mass (11 g) by the molar mass (44.01 g/mol):
Number of moles of CO2 = 11 g / 44.01 g/mol
Next, using the ratio from the balanced equation, we can determine the number of moles of lithium hydroxide needed. Since the ratio is 2:1, we can simply divide the moles of carbon dioxide by 2:
Number of moles of LiOH = (11 g / 44.01 g/mol) / 2
Finally, to find the mass of lithium hydroxide needed, we multiply the number of moles of LiOH by its molar mass. The molar mass of lithium hydroxide (LiOH) can be calculated by adding the atomic masses of lithium (Li), oxygen (O), and hydrogen (H):
The atomic mass of lithium (Li) is approximately 6.94 g/mol, oxygen (O) is approximately 16.00 g/mol, and hydrogen (H) is approximately 1.01 g/mol.
Thus, the molar mass of lithium hydroxide is:
6.94 g/mol + 16.00 g/mol + 1.01 g/mol = 23.95 g/mol
Finally, we can determine the mass of lithium hydroxide needed by multiplying the number of moles of LiOH by its molar mass:
Mass of LiOH = Number of moles of LiOH * Molar mass of LiOH
This calculation will give us the mass of lithium hydroxide needed to react with 11 grams of carbon dioxide.