If angle AFB= 8x-6 and angle BFC= 14x +8, find the value of x so that angle AFC is a right angle.
right angle means 90º
so
8x-6 + 14x +8 = 90
22x = 90 + 6 - 8
22x = 88
x = 4
exactly the same idea as
http://www.jiskha.com/display.cgi?id=1254075681
Thank you but I just don't understand the whole equation thing tho.
What grade level is this geometry ?
Doing these kind of questions without knowing how to solve basic equations would be like learning how to play hockey without knowing how to skate.
this is 10th grade math. Im not very smart just to let you know.
But thank you anyways
I know you've helped me alot but is there anyway that you can help me understand two more problems. Geometry andGeometry again again again again
To find the value of x so that angle AFC is a right angle, we need to use the properties of angles in a triangle. In a triangle, the sum of the angles is always 180 degrees.
Given that angle AFB is 8x-6 and angle BFC is 14x+8, we can set up an equation to represent the sum of these angles with the angle AFC.
Angle AFB + Angle BFC + Angle AFC = 180
Substituting the given values into the equation:
(8x-6) + (14x+8) + Angle AFC = 180
Combining like terms:
22x + 2 + Angle AFC = 180
Now, we know that angle AFC is a right angle, which means it measures 90 degrees. Therefore, we can substitute 90 for Angle AFC in the equation:
22x + 2 + 90 = 180
Simplifying:
22x + 92 = 180
To isolate x, we subtract 92 from both sides of the equation:
22x = 180 - 92
22x = 88
Finally, we divide both sides by 22 to solve for x:
x = 88 / 22
x = 4
Therefore, the value of x that makes angle AFC a right angle is 4.