EVALUATW (-8B)^2 AND -8B^2 WHEN B=10.
(-8B^2)=
-8B^2=
SOLVE USING THE ADDITION PRINCIPLE.
3.8=S=0.1. THE SOLUTION IS S=
THANK YOU
To evaluate (-8B)^2 when B = 10, you need to substitute the value of B into the expression and perform the necessary calculations.
(-8B)^2
= (-8 * 10)^2
= (-80)^2
= 6400
Therefore, (-8B)^2 when B = 10 is equal to 6400.
To evaluate -8B^2 when B = 10, you also need to substitute the value of B and perform the calculations.
-8B^2
= -8 * (10)^2
= -8 * 100
= -800
Therefore, -8B^2 when B = 10 is equal to -800.
Regarding the equation 3.8 = s = 0.1, it seems there might be a typo or mistake. It is not clear what you are trying to solve or what the equation is referring to.
If you meant to say "solve the equation 3.8 = s + 0.1," then to solve using the addition principle, you need to isolate the variable s by subtracting 0.1 from both sides of the equation.
3.8 = s + 0.1
3.8 - 0.1 = s + 0.1 - 0.1
3.7 = s
Therefore, the solution to the equation 3.8 = s + 0.1 is s = 3.7.
If you meant something else or have additional information, please let me know.