x^2-3x+2<0

Put in y=x^2-3x+2 in your graphing calculator, and graph is. See where y is negative. That area is the solution
The graph will be a second degree equation, and probably cross the y=0 axis at the x defined in (x^2-3x+2=0)
Factor that equation and solve for those values of x. There will be two of them, and that will divide the x axis into three regions (to the left of the most negative, between the two values of x, and to the right of the highest value)
Test each region by picking an x and seeing if the value of y=x^2-3x+2 is negative.
(x-1)(x-2)

x=1 x=2

You have deposited 1000$ in your saving account with an anual interst rate of 4 percent compund monthly. How much money are you going to have in your account after six months.

To calculate the amount of money in your account after six months, using compound interest, you can follow these steps:

1. Convert the annual interest rate to a monthly interest rate. Since the interest is compounded monthly, divide the annual interest rate by 12. In this case, the monthly interest rate would be 4% / 12 = 0.04 / 12 = 0.00333 (approximately).

2. Calculate the monthly interest by multiplying the current balance by the monthly interest rate. Since you initially deposited $1000, the monthly interest would be 0.00333 * $1000 = $3.33 (approximately).

3. Add the monthly interest to the current balance to get the new balance for each month. In this case, after the first month, you would have $1000 + $3.33 = $1003.33 (approximately).

4. Repeat steps 2 and 3 for the remaining five months, continuously adding the monthly interest to the balance each time.

5. After the sixth month, the final balance in your account would be the amount you calculated in step 4.

Note: In practice, most banks or financial institutions use complicated formulas to account for various factors such as compounding periods, interest adjustments, and fees. It's essential to consult your bank or refer to the terms and conditions specific to your account to get precise information about your savings.