A house painter uses a chair and pulley arrangement to lift himself up the side of a house. The painter's mass is 69.2 kg and the chair's mass is 24.0 kg. With what force must he pull down on the rope in order to accelerate upward at 0.379 m/s2?
To find the force with which the painter must pull down on the rope, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
- The painter's mass (m1) = 69.2 kg
- The chair's mass (m2) = 24.0 kg
- The acceleration (a) = 0.379 m/s^2
We need to find the force (F) with which the painter must pull down on the rope.
First, let's calculate the total mass of the system:
Total mass (m) = mass of the painter (m1) + mass of the chair (m2)
= 69.2 kg + 24.0 kg
= 93.2 kg
Next, we can calculate the force using Newton's second law:
F = m * a
Substituting the known values:
F = 93.2 kg * 0.379 m/s^2
F = 35.28 N
Therefore, the painter must pull down on the rope with a force of approximately 35.28 Newtons in order to accelerate upward at 0.379 m/s^2.