Okay so I need help with this question:
How many grams of NH3 can be produced from 3.87 mol of N2?
Can someone tell me how to do this probelm?
Maybe do the question with a different set of numbers just so that I can see how to do it?
Thank you!
There are two atoms of N per mole of N2; therefore, you should be able to produce 2 moles NH3 per 1 mole N2. Convert moles to g by # g = moles x molar mass
the% by mass of h2o in the salt cu(no3)2.6h2o equals
Sure! I'd be happy to help you with that question. To find out how many grams of NH3 can be produced from a given amount of N2, you need to use the balanced chemical equation for the reaction of N2 with H2 to produce NH3.
The balanced chemical equation for this reaction is:
N2 + 3H2 → 2NH3
From the equation, you can see that for each mole of N2, you need 3 moles of H2 to produce 2 moles of NH3.
To solve the problem, follow these steps:
Step 1: Determine the molar mass of N2 and NH3. The molar mass of N2 is 28.02 g/mol, and the molar mass of NH3 is 17.03 g/mol.
Step 2: Calculate the number of moles of NH3 using the given moles of N2. You can use the conversion factor from the balanced chemical equation to find the moles of NH3.
Given: Moles of N2 = 3.87 mol
Conversion factor: 2 mol NH3 / 1 mol N2
Calculate:
Moles of NH3 = 3.87 mol N2 × (2 mol NH3 / 1 mol N2) = 7.74 mol NH3
Step 3: Convert moles of NH3 to grams. To do this, multiply the moles of NH3 by the molar mass of NH3.
Molar mass of NH3 = 17.03 g/mol
Calculate:
Grams of NH3 = 7.74 mol NH3 × 17.03 g/mol NH3 = 131.95 g NH3
Therefore, 3.87 mol of N2 can produce 131.95 grams of NH3.
If you have a different set of numbers, please provide them, and I can help you work through the problem using those values.
Sure, I can help you with that! To solve this problem, we can use the balanced chemical equation for the reaction of nitrogen gas (N2) with hydrogen gas (H2) to form ammonia gas (NH3):
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
Let's do the problem with a different set of numbers so that you can see how to solve it step by step. Suppose we are given 2.5 moles of N2. We need to determine how many grams of NH3 can be produced.
Step 1: Convert moles of N2 to moles of NH3
Using the mole ratio from the balanced equation, we know that 1 mole of N2 produces 2 moles of NH3.
2.5 mol N2 x (2 mol NH3 / 1 mol N2) = 5 mol NH3
Step 2: Convert moles of NH3 to grams
To do this, we need to know the molar mass of NH3, which can be calculated as follows:
1 nitrogen atom (N) = 14.01 g/mol
3 hydrogen atoms (H) = 3.03 g/mol (1.01 g/mol x 3)
Molar mass of NH3 = 14.01 g/mol + 3.03 g/mol = 17.04 g/mol
Now we can convert moles of NH3 to grams:
5 mol NH3 x (17.04 g NH3 / 1 mol NH3) = 85.2 g NH3
So, with 2.5 moles of N2, we can produce 85.2 grams of NH3.
Now, you can apply the same steps to your original problem with 3.87 mol N2.