In the gas phase reaction
CH4 + H2O → CO + 3 H2 At T = 1500 K , Kp = 11000
Calculate Kp, T = 1500 K , for the following reaction
3 CO + 9 H2 → 3 CH4 + 3 H2O .
The reaction in the question is the reverse of the reaction given. That is just 1/Kp or 1/11000 = ??
thanks! yes it is I figured it out, it's (1/11000)^3
To calculate Kp for the given reaction, we need to write the balanced equation for the reaction and then use the given Kp value to determine the new Kp value.
The balanced equation for the reaction is:
3CO + 9H2 → 3CH4 + 3H2O
First, let's determine the relationship between the given reaction and the reaction with the known Kp value. We can do this by comparing the stoichiometric coefficients of the balanced equations.
From the given equation, we can see that:
1 CO is equivalent to 1/3 CH4
1 H2 is equivalent to 1/3 H2O
Now, we can convert the given Kp value using these relationships. Since Kp is a measure of partial pressures, we need to consider the stoichiometric coefficients and their powers.
For the given reaction:
Kp = 11000
Using the stoichiometric coefficients, we can determine the new Kp value:
Kp' = (Kp)^n
= (11000)^3
= 1.331 x 10^10
Therefore, at T = 1500 K, the new Kp value for the reaction:
3CO + 9H2 → 3CH4 + 3H2O
is 1.331 x 10^10.