In the figure below, a box of Cheerios (mass mC = 1.0 kg) and a box of Wheaties (mass mW = 3.5 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 4.2 N. If the magnitude of is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?
->MC.MW------
Friction on Cheerios, Fc=2.0 N
Friction on Wheaties, Fw=4.2 N
"If the magnitude of is 12 N,"
The sentence seems incomplete, and a confirmation/description of the figure is required.
10
9.0
To find the magnitude of the force on the Wheaties box from the Cheerios box, we can apply Newton's second law of motion. According to this law, the net force on an object is equal to the product of its mass and acceleration.
In this case, the net force acting on the Wheaties box is the force applied to the Cheerios box (12 N) minus the frictional force acting on the Wheaties box (4.2 N). So, we have:
Net force on Wheaties box = Force on Cheerios box - Frictional force on Wheaties box
Let's assign some symbols:
Net force on Wheaties box = FnetW
Force on Cheerios box = F
Frictional force on Wheaties box = FfW
Given that the frictional force on the Wheaties box is 4.2 N, we have:
FfW = 4.2 N
And the magnitude of the force applied to the Cheerios box is 12 N:
F = 12 N
Now, substituting these values into the equation for the net force on the Wheaties box:
FnetW = F - FfW
FnetW = 12 N - 4.2 N
FnetW = 7.8 N
Therefore, the magnitude of the force on the Wheaties box from the Cheerios box is 7.8 N.