How many molecules of glycerol (C3, H8, O3) would be present in 1 L of M glycerol solution?

I am thinking it is 6.02 x 10^23 but have also heard conflicting opinions.

You don't give the molarity of the C3H8O3. 1 mole of anything contains 6.02 x 10^23 molecules of that "thing." Therefore, if it is 1 M, it contains 1 mol/L and will contain 1 mole of molecules. I hope this helps.

sorry, it was how many molecules of glycerol would be present in 1 L of a 1 M glycerol solution.

So you have your answer since I assumed a 1 M soln for my previous answer.

How many molecules of glycerol would be in 1 L of a M glycerol solution?

14

To determine the number of molecules of glycerol in 1 L of a M glycerol solution, you need to know the molarity (M) of the solution. Without the molarity value, it is not possible to calculate the number of molecules accurately. Could you please provide the molarity of the glycerol solution?

To determine how many molecules of glycerol would be present in 1 L of a 1 M glycerol solution, you need to know the Avogadro's number and the molar mass of glycerol.

1 mole of any substance contains 6.02 x 10^23 molecules, which is Avogadro's number.

The molar mass of glycerol (C3H8O3) is the sum of the atomic masses of carbon (C), hydrogen (H), and oxygen (O) atoms in glycerol. The atomic masses of C, H, and O are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively.

So, the molar mass of glycerol is:
(3 * 12.01 g/mol) + (8 * 1.01 g/mol) + (3 * 16.00 g/mol) = 92.09 g/mol

Now, since you specified a 1 M glycerol solution, this means that 1 mole of glycerol is dissolved in 1 liter of solution.

Therefore, in 1 L of a 1 M glycerol solution, you would have 6.02 x 10^23 molecules of glycerol since 1 mole of glycerol contains 6.02 x 10^23 molecules.

I hope this clarifies your question!