What's the easiest way to solve this problem
-1.28 = Sigma^-1 (25 - Mu)
1.28 = Sigma^-1 (475 - Mu)
were Sigma and Mu are each different varialbes that are constant...
Thanks
Rewrite the equations as:
-1.28 =(25 - μ)/σ .... (1)
1.28 = (475 - μ)/σ .... (2)
Divide (2) by (1) to get
(475-μ)/(25-μ) = 1
Solve for μ and back substitute in (1) or (2).
μ=250, σ=175 approx.
To solve this problem, we can follow these steps:
Step 1: Start by isolating the expression containing the variable "Sigma."
-1.28 = Sigma^-1 (25 - Mu)
Take the inverse of both sides to get:
1 / -1.28 = 1 / (Sigma^-1 (25 - Mu))
Multiply both sides by (Sigma^-1) to get:
(Sigma^-1) / -1.28 = 1 / (25 - Mu)
Step 2: Next, isolate the expression containing the variable "Mu."
1.28 = Sigma^-1 (475 - Mu)
Take the inverse of both sides to get:
1 / 1.28 = 1 / (Sigma^-1 (475 - Mu))
Multiply both sides by (Sigma^-1) to get:
(Sigma^-1) / 1.28 = 1 / (475 - Mu)
Step 3: Set the two expressions obtained in Step 1 and Step 2 equal to each other and solve for "Sigma" and "Mu."
(Sigma^-1) / -1.28 = (Sigma^-1) / 1.28, and
(1 / (25 - Mu)) = (1 / (475 - Mu))
Cross-multiply the fractions to eliminate the denominators:
(Sigma^-1) * 1.28 = (Sigma^-1) * -1.28
25 - Mu = 475 - Mu
The variable "Mu" cancels out, and we're left with:
25 = 475
This equation is not solvable since 25 is not equal to 475.
Hence, there is no solution to this problem based on the given equations.