help someone please:

In 1993 the life expectancy of males in a certain country was 71.2 years. In 1997 it was 73.4 years. Le E represent the life expectancy in year t represent the number of years since 1993

E(t)= ___t + ___ ?

use the function to predict the life expectancy of males in 2009
E(16)=?

Basically, you count the number of years from 1933 to 1997 which is 64 years and see how much the life expectancy has increased. That will be 73.4 - 71.2 = 2.2 years. How much is that per year. That will be 2.2/64 = 0.03438. So the E(t) from 1933 would be 0.03438(t) + 64. Your question doesn't ask for the year since 1933 but for the year since 1993. Can't you calculate the amount that should be subtracted from 1997 (or added to the year 1933) so you start from 1993 instead of 1997.

To find the equation for the life expectancy, we need to determine the rate of change and the initial value. The given information tells us that in 1993, the life expectancy was 71.2 years, and in 1997 it increased to 73.4 years.

Let's calculate the rate of change:
Rate of change = (Change in life expectancy) / (Change in years)
= (73.4 - 71.2) / (1997 - 1993)
= 2.2 / 4
= 0.55

So, the rate of change is 0.55.

Now, let's find the initial value:
Since the life expectancy of males in the year 1993 was 71.2 years, we can assign that value to t = 0 in our equation.

Therefore, the equation for the life expectancy is:
E(t) = 0.55t + 71.2

To predict the life expectancy in 2009, we substitute t = 16 into the equation:

E(16) = 0.55(16) + 71.2
= 8.8 + 71.2
= 80 years

So, the predicted life expectancy of males in 2009 would be 80 years.