Solve. x^2+6x-4=0 x=-3+�ã13,-3-�ã13
you are correct.
x = -3 ± √13
(You can obtain a √ sign on a PC by holding down the Alt key and at the same time presing 251 on the number pad, then releasing the Alt key)
thanks for your help
To solve the quadratic equation x^2 + 6x - 4 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 1, b = 6, and c = -4. Substituting these values into the formula, we get:
x = (-(6) ± √((6)^2 - 4(1)(-4))) / (2(1))
Simplifying further:
x = (-6 ± √(36 + 16)) / 2
x = (-6 ± √52) / 2
x = (-6 ± 2√13) / 2
Now, we can simplify this expression by dividing both the numerator and denominator by 2:
x = -3 ± √13
So, the solutions to the quadratic equation x^2 + 6x - 4 = 0 are:
x = -3 + √13
x = -3 - √13