For a liquid, 0.500 cubic meters weighs 4590 N. What is the specific gravity of the liquid?

density = mass/volume

d = 4590/0.500 = ?? N/m^3

Here is a quick rundown of the way I think it should be done:

If the weight is 4590 N,
m = W/g, or
m = 4590 N / 9.8 kg/N = 468.4 kg
d = 468.4 kg / 0.500 m^3 = 937 kg/m^3
1 m^3 = 1000 dm^3
0.500 m^3 = 500 dm^3
d = 468.4 kg / 500 dm^3 = 0.937 kg/dm^3
It can be shown that a density of
0.937 kg/dm^3 is equivalent to 0.937 g/cm^3
The specific gravity is the ratio of the densities of the material divided by the density of water:
0.937 g/cm^3 / 1.00 g/cm^3 = 0.937 (unitless value)

To find the specific gravity of a liquid, we need to compare its density to the density of water. The specific gravity (SG) is defined as the ratio of the density of the liquid to the density of water.

The equation for specific gravity can be written as:

SG = ρ_liq / ρ_water

where ρ_liq is the density of the liquid and ρ_water is the density of water.

Since the given information provides the weight of the liquid, we need to convert it into density by dividing the weight by the volume. The formula for density (ρ) is:

ρ = m / V

where m is the mass of the liquid and V is the volume.

To find the mass of the liquid, we can use the weight given in Newtons and convert it to kilograms using the acceleration due to gravity (9.8 m/s^2):

m = W / g

where W is the weight of the liquid and g is the acceleration due to gravity (9.8 m/s^2).

Once we have the mass (m) and volume (V) of the liquid, we can calculate the density (ρ). Then, we can compare the density of the liquid to the density of water to find the specific gravity (SG).

Let's calculate it step by step:

Step 1: Calculate the mass of the liquid.
Given weight, W = 4590 N
Acceleration due to gravity, g = 9.8 m/s^2

m = W / g = 4590 N / 9.8 m/s^2

Step 2: Convert the mass from Newtons to kilograms.
1 N = 1 kg.m/s^2

m (kg) = m (N) / g = 4590 N / 9.8 m/s^2

Step 3: Calculate the density of the liquid.
Given volume, V = 0.500 cubic meters

ρ = m / V = m (kg) / V

Step 4: Compare the density of the liquid to the density of water.
The density of water is approximately 1000 kg/m^3.

SG = ρ_liq / ρ_water

Now plug in the values and calculate the specific gravity (SG).