5/6(12z-24)>2/5(25z-25>
Help please?
i mean 5/6(12z-24)>2/5z-25)
original question:
expand first
10z - 20 > 10z - 10
-20 > -10
false, so there is no solution to your inequation.
in your revision check your typing.
I have a feeling that is not what you want to say
is it (2/5)x - 25 ?
is it 2/5(x-25) ?
It's 5/6(12z-24)>2/5(25z-25)
What IS the answer?
To solve this inequality, we'll start by simplifying the expression on both sides of the equation and then isolate the variable, z.
Step 1: Simplify the expression on both sides of the inequality.
On the left side, we have: 5/6(12z - 24)
To simplify, distribute the 5/6 to both terms inside the parentheses:
5/6 * 12z = (5/6) * 12 * z = (60/6) * z = 10z
5/6 * -24 = (5/6) * (-24) = (-120/6) = -20
So on the left side, the inequality becomes: 10z - 20
On the right side, we have: 2/5(25z - 25)
To simplify, distribute the 2/5 to both terms inside the parentheses:
2/5 * 25z = (2/5) * 25 * z = (50/5) * z = 10z
2/5 * -25 = (2/5) * (-25) = (-50/5) = -10
So on the right side, the inequality becomes: 10z - 10
Now, the inequality becomes: 10z - 20 > 10z - 10
Step 2: Isolate the variable, z.
To isolate z, we'll get rid of the constant terms on both sides of the inequality. Subtracting 10z from both sides cancels out the z terms:
10z - 10z - 20 > 10z - 10z - 10
Simplifying further, we have:
-20 > -10
Step 3: Analyze the inequality.
The inequality -20 > -10 is true.
This means that the inequality 5/6(12z - 24) > 2/5(25z - 25) is true for all values of z since the inequality holds for any value of z.
Therefore, the solution to the inequality is all real numbers for z, or z ∈ ℝ.