The acid-base reaction between phosphoric acid, H3PO4, and calcium hydroxide, Ca(OH)2, yields water and calcium phosphate. For each mole of calcium phosphate produced by this reaction, how many moles of water are also produced?
Write the balanced equation and compare the coefficients in the equation.
3Ca(OH)2 + 2H3PO4 ==> Ca3(PO4)3 + 6H2O
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The balanced chemical equation for the reaction between phosphoric acid (H3PO4) and calcium hydroxide (Ca(OH)2) is:
2 H3PO4 + 3 Ca(OH)2 → 6 H2O + Ca3(PO4)2
From the balanced equation, we can see that for every 6 moles of water (H2O) produced, we also get 1 mole of calcium phosphate (Ca3(PO4)2) produced.
Therefore, for each mole of calcium phosphate produced by this reaction, 6 moles of water are also produced.
To determine the number of moles of water produced, we need to consider the balanced chemical equation for the reaction between phosphoric acid (H3PO4) and calcium hydroxide (Ca(OH)2).
The balanced chemical equation for the reaction is as follows:
2 H3PO4 + 3 Ca(OH)2 → Ca3(PO4)2 + 6 H2O
From the balanced equation, we can see that for every 2 moles of H3PO4 and 3 moles of Ca(OH)2, we obtain 1 mole of Ca3(PO4)2 and 6 moles of water (H2O).
Therefore, for each mole of calcium phosphate produced by this reaction, 6 moles of water are also produced.