A 10000 car comes to a bridge during a storm and finds the bridge washed out. The 750 driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 22.8 above the river, while the opposite side is a mere 5.60 above the river. The river itself is a raging torrent 65.0 wide

Drew Brees

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To solve this problem, we can use the concept of projectile motion.

First, let's determine the horizontal distance the car needs to jump. The width of the river is given as 65.0 meters.

Next, we need to find the height difference between the starting point (22.8 meters) and the landing point (5.60 meters). This is the vertical distance the car needs to travel.

We can use the equations of motion to calculate the time it takes for the car to reach the landing point when it jumps off the edge.

The equation to find the time of flight is:
t = sqrt((2 * h) / g)

where t is the time of flight, h is the vertical distance, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Once we have the time of flight, we can calculate the horizontal distance the car will travel during that time using the equation:

d = v * t

where d is the horizontal distance and v is the velocity of the car.

To find the velocity, we need to use the equation of motion for vertical velocity:
v = sqrt(2 * g * h)

Substituting the values we have, we can find the velocity.

Finally, we can multiply the time of flight by the horizontal velocity to get the horizontal distance the car will travel.

Let's plug in the values and calculate:

Vertical difference (h) = 22.8 m - 5.60 m = 17.2 m
Acceleration due to gravity (g) = 9.8 m/s^2

Time of flight (t) = sqrt((2 * 17.2 m) / 9.8 m/s^2) ≈ 2.83 s

Velocity (v) = sqrt(2 * 9.8 m/s^2 * 17.2 m) ≈ 18.37 m/s

Horizontal distance (d) = 18.37 m/s * 2.83 s ≈ 51.96 m

Therefore, the car needs to jump approximately 51.96 meters to successfully make it to the other side of the river.