A ramp has a rise of 8 and a run of 10, what's the slope? I'm not sure how to solve it.
The other question is to find the slope of the line that passes through 17/2, 8) and (5/2,-1)
I did -1 - 8 is 7 and 5/2 - 17/2 as -12/2 so 7/ -12/2 is 7/-6
The slope is rise divided by run, by definition. "Solve" it by performing the division of 8 by 10.
In your second question, -1 - 8 is not 7
10 std Find the equation of a line whose inclination is 30° and making an intercept-3 on the y-axis
To find the slope of a ramp with given rise and run, you can use the formula for slope: slope = rise / run. In this case, the rise is 8 and the run is 10.
So, the slope of the ramp is 8/10, which simplifies to 4/5.
Now let's move on to the second question about finding the slope of the line passing through the points (17/2, 8) and (5/2, -1).
To find the slope, we can use the formula: slope = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.
From your calculations, it seems like you mistakenly subtracted -1 from 8, which resulted in 7. Remember to subtract y2 from y1 and not the other way around.
Let's solve it step by step.
(y2 - y1) = -1 - 8 = -9
(x2 - x1) = 5/2 - 17/2 = -12/2 = -6
So, the slope of the line passing through the points (17/2, 8) and (5/2, -1) is -9 / -6, which simplifies to 3/2.