A man walking his three dogs meets his brother who is walking his two dogs. How many feet are there in total when they meet?????????
Various answers....
Only two feet as I have assumed that both the man and his brother have one leg.
The dogs do not count as they do not have feet they have paws.
Another one.........
Zero feet, because they have met there is zero distance between them.
2*2+3*4+3*4=24 feet/paws
Plus 5 leashes of 6 feet each = 30 feet.
That makes 54 feet in all.
To determine the total number of feet when they meet, we first need to consider the number of dogs involved. The man has three dogs, and his brother has two dogs. Each dog has four legs, as dogs are quadrupeds.
The man's three dogs would contribute (3 dogs * 4 legs per dog =) 12 legs to the total number of feet when they meet.
Similarly, the brother's two dogs would contribute (2 dogs * 4 legs per dog =) 8 legs to the total number of feet.
When they meet, the total number of feet would be the sum of the legs from both sets of dogs. So, we add 12 legs (from the man's dogs) and 8 legs (from the brother's dogs) to get a total of (12 legs + 8 legs =) 20 legs.
Since each leg corresponds to one foot, the total number of feet when they meet would be 20 feet.