Suppose the position of an object is given by ->r(vector) = (3.0t^2*ihat - 6.0t^3*jhat)m. Where t in seconds.

Determine its velocity ->v as a function of time t.

Determine its acceleration ->a as a function of time t.

Determine ->r at time t = 2.5 s.

Determine ->v at time t = 2.5s

velocity is the first derivative of position.

v=6.0t i -18.0 t^2 j
acceleration is the second derivative of position or
a= 6.0 i -36 t j

To determine the velocity ->v as a function of time t, we need to differentiate the position vector ->r with respect to time t.

Given ->r = (3.0t^2 * ihat - 6.0t^3 * jhat) m, we can differentiate each component with respect to time t.

Differentiating the x-component (3.0t^2 * ihat) with respect to time t gives us the x-component of the velocity ->v:

vx = d(3.0t^2)/dt = 6.0t

Differentiating the y-component (-6.0t^3 * jhat) with respect to time t gives us the y-component of the velocity ->v:

vy = d(-6.0t^3)/dt = -18.0t^2

Combining these components, the velocity vector ->v as a function of time t is:

->v = (6.0t * ihat - 18.0t^2 * jhat) m/s

To determine the acceleration ->a as a function of time t, we need to differentiate the velocity vector ->v with respect to time t.

Differentiating the x-component (6.0t * ihat) with respect to time t gives us the x-component of the acceleration ->a:

ax = d(6.0t)/dt = 6.0

Differentiating the y-component (-18.0t^2 * jhat) with respect to time t gives us the y-component of the acceleration ->a:

ay = d(-18.0t^2)/dt = -36.0t

Combining these components, the acceleration vector ->a as a function of time t is:

->a = (6.0 * ihat - 36.0t * jhat) m/s^2

To determine the position vector ->r at time t = 2.5 s, we substitute t = 2.5 into the given position vector ->r:

->r(2.5) = (3.0(2.5)^2 * ihat - 6.0(2.5)^3 * jhat) m

Calculating the expression gives us the position vector ->r at time t = 2.5 s.

To determine the velocity vector ->v at time t = 2.5 s, we substitute t = 2.5 into the velocity vector ->v:

->v(2.5) = (6.0(2.5) * ihat - 18.0(2.5)^2 * jhat) m/s

Calculating the expression gives us the velocity vector ->v at time t = 2.5 s.

suppose the position of an object is given by r = (3.0 t^2-i - 6.0t^3 j)m.(a) determine its velocity v and acceleration a, as a function of time. (b) determine r and v at time t = 2.5 s.