I'm sooooooo not sure if I'm doing this right, but can someone check it please? Thanks :))
5) Determine the mass in grams of 3.01 x 10^23 atoms of Cl (element)
I got 17.5 grams...is this right?
I don't get the same number but close.
The atomic mass I used was 35.4527 which I rounded to 35.453; then,
35.453 x (3.01 x 10^23/6.02 x 10^23) = 35.453 x (1/2) = 17.7265 which rounds to 17.7 g to three significant figures.
Oh okay thank you very much! :D
To calculate the mass in grams of a given number of atoms, you need to follow these steps:
Step 1: Find the molar mass of the element. In this case, we're dealing with chlorine (Cl), so the molar mass can be found on the periodic table. The molar mass of chlorine is approximately 35.45 g/mol.
Step 2: Convert the given number of atoms (3.01 x 10^23) to moles. One mole of any substance contains 6.022 x 10^23 particles (Avogadro's number).
To convert atoms to moles, divide the given number of atoms by Avogadro's number:
3.01 x 10^23 atoms / (6.022 x 10^23 atoms/mol) = 0.5 mol
Step 3: Multiply the number of moles by the molar mass of the element to find the mass in grams.
0.5 mol x 35.45 g/mol = 17.725 grams (rounded to 3 decimal places)
So the correct answer is approximately 17.725 grams, not 17.5 grams.