how do i solve this linear equation:
3x/4 + 6 = -12 (3x over 4 is a fraction)
and this quadratic equation.....
-4x squared = 0??
just multiply each term by 4 to get
3x + 24 = -48
3x = -72
x = 24
yes, your second equation is a quadratic.
1) multiply both sides by 4/3
x+6*4/3=-12*4/3
does that help?
2) Yes, a quadratic. it is a trivial equation.
ok, on the first one, after x = -72, where did you get x = 24?
and for the second problem, how am I to solve it??
To solve the linear equation 3x/4 + 6 = -12, you can follow these steps:
Step 1: Eliminate the fraction by multiplying every term in the equation by 4.
4 * (3x/4) + 4 * 6 = 4 * -12
3x + 24 = -48
Step 2: Simplify the equation by subtracting 24 from both sides.
3x + 24 - 24 = -48 - 24
3x = -72
Step 3: Solve for x by dividing both sides of the equation by 3.
3x/3 = -72/3
x = -24
Therefore, the solution to the linear equation is x = -24.
Now, let's move on to the quadratic equation -4x^2 = 0.
Step 1: Rearrange the equation so that it is in the standard form, with all terms on one side equal to zero.
-4x^2 + 0 = 0
Step 2: Simplify the equation if needed. In this case, the equation is already simplified.
Step 3: Solve for x by factoring or using the quadratic formula. However, this equation can be solved even more simply.
Since the equation is -4x^2 = 0, we can conclude that for the equation to be true, the value of x must be zero. Therefore, the solution to the quadratic equation is x = 0.
I hope this explanation helps! If you have any more questions, feel free to ask.