3x+4y=12 solve for solution (0.)(.3/4) (,0) (8/3,)

You are given the equation, and the x,y set. Iwill be happy to critique your work. Here is one as an example:

3x+4y=12 solve for solution (.3/4)
3x + 4(3/4)=12
3x + 3=12
3x=9
x=3

To solve for the solution (0, .3/4), substitute the given values for x and y into the equation.

Replacing x with 0 and y with .3/4, you have:

3(0) + 4(.3/4) = 12

This simplifies to:

0 + .3 = 12

Notice that .3 = 3/10, so the equation becomes:

0 + 3/10 = 12

Now, combine like terms:

3/10 = 12

To isolate x, you need to move the terms around. To do this, subtract 3/10 from both sides of the equation:

3/10 - 3/10 = 12 - 3/10

This simplifies to:

0 = 120/10 - 3/10

Combine like terms:

0 = 117/10

Since the equation is equal to 0, but 117/10 is not 0, the point (0, .3/4) is not a solution to the equation.