3x+4y=12 solve for solution (0.)(.3/4) (,0) (8/3,)
You are given the equation, and the x,y set. Iwill be happy to critique your work. Here is one as an example:
3x+4y=12 solve for solution (.3/4)
3x + 4(3/4)=12
3x + 3=12
3x=9
x=3
To solve for the solution (0, .3/4), substitute the given values for x and y into the equation.
Replacing x with 0 and y with .3/4, you have:
3(0) + 4(.3/4) = 12
This simplifies to:
0 + .3 = 12
Notice that .3 = 3/10, so the equation becomes:
0 + 3/10 = 12
Now, combine like terms:
3/10 = 12
To isolate x, you need to move the terms around. To do this, subtract 3/10 from both sides of the equation:
3/10 - 3/10 = 12 - 3/10
This simplifies to:
0 = 120/10 - 3/10
Combine like terms:
0 = 117/10
Since the equation is equal to 0, but 117/10 is not 0, the point (0, .3/4) is not a solution to the equation.