Lately I just have blacked out in my algebra 1 class. Here's a equation on my worksheet, and I would be happy if you could show in steps how you got your answer. Thank you.
(2x²+5x+3)-(x²+2x+1)
this is not an equation, it probably says to "simplify" it.
(2x²+5x+3)-(x²+2x+1)
how about pretending to see it as :
1(2x²+5x+3)-1(x²+2x+1) , then
= 2x²+5x+3-x²-2x-1
= x²+3x+2
Yes it does say simplify it, I'm sorry. I understand how you got that, but what if I had something like this.
4x-2xy+3x²+y+5xy+x²y
You start by ordering the terms. The priority of ordering is
1. name of variable in alphabetical order.
For example, put 2xy before y²
2. power of variable in descending order.
Example: x²y is placed before xy²
3. The constant term will be placed at the end.
After that, you would have collected like terms together. Add/subtract like terms. For example, 2x²y + 4x²y = 6x²y.
For 4x-2xy+3x²+y+5xy+x²y
Ordering gives
3x² + x²y + 4x + 5xy - 2xy + y
Add like terms, if any (5xy-2xy=3xy)
3x² + x²y + 4x + 3xy + y
That is all you can do. You cannot add/subtract unlike terms.
x²y and -2yx² are like terms.
xy and 3x² are unlike terms.
Of course! Let's walk through the steps to simplify the equation:
Step 1: Distribute the negative sign
In the given equation, we have (2x²+5x+3)-(x²+2x+1). To simplify this, we need to distribute the negative sign to all terms within the parentheses following the equation -(x²+2x+1).
Distributing the negative sign changes the signs of each term within the parentheses:
(2x²+5x+3)-x²-2x-1
Step 2: Combine like terms
Now that the negative sign has been distributed, we can combine like terms. Like terms are terms that have the same variable(s) and exponent(s).
Starting with the x² terms, we have 2x²-x², which equals x².
Next, we look at the x terms. We have 5x-2x, which equals 3x.
Finally, we combine the constant terms: 3-1, which equals 2.
After combining all the like terms, we end up with the simplified equation:
x²+3x+2
Therefore, the simplified form of (2x²+5x+3)-(x²+2x+1) is x²+3x+2.