Bill finds an unusual object and wishes to calculate it's density. He discovers a problem of accurately weighing it, because it won't stay on the weighing pan. To solve this he adds the object to a beaker containing 161 mL of distilled water and finds the water level rises to 190 mL. The flask of water weighed 955.5 grams after the object was added. If the empty beaker weighed 669 grams, what is the weight of the water?
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This is a slightly different post that the one above. But my comments will be the same? How much of this do you know how to do? How much have you done? What do you not understand about it?
To determine the weight of the water, we need to subtract the weight of the empty beaker from the weight of the beaker with the water. Let's calculate it step by step.
Step 1: Find the weight of the beaker with the water.
Weight of beaker with water = Weight of beaker + Weight of water
The weight of the empty beaker is given as 669 grams.
Step 2: Calculate the weight of the water by subtracting the weight of the empty beaker from the weight of the beaker with the water.
Weight of water = Weight of beaker with water - Weight of empty beaker
Since the weight of the beaker with water is given as 955.5 grams:
Weight of water = 955.5 grams - 669 grams
Step 3: Calculate the difference in volume between the two water levels.
The initial volume of the water in the beaker is 161 mL, and after adding the object, the volume rises to 190 mL.
Difference in volume = Final volume - Initial volume
Difference in volume = 190 mL - 161 mL
Step 4: Calculate the density of water.
Density of water = Weight of water / Difference in volume
Now we can substitute the values into the equation:
Density of water = (955.5 grams - 669 grams) / (190 mL - 161 mL)
Simplifying,
Density of water = 286.5 grams / 29 mL
Density of water = 9.879 grams/mL
So, the density of water is approximately 9.879 grams per milliliter.