3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
rather silly question, and some of it makes no sense
eg look at the first part
......-2(4-5)2-1
does this end up -2(-1)(2) ? or did you forget an operator before the last 2?
there is a similar discrepancy near the end of the mess.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
First, get rid of the parentheses within the parentheses by combining those terms. I will assume a plus sign in front of the third 2 and the last 1.
3(2+3-2(4-5)2-1)-3(2+4(4-2)-8+3(2-5)+1-2)1-3)+4-5
3(2+3+1+2-1)-3(2+8-8-9+1-2+1-3)+4-5
Next combine terms within the parentheses, multiply and then add the products.
I hope this helps. Thanks for asking.
To solve the given expression, let's break it down step by step:
1. Simplify the innermost parentheses first:
- In the first part, (-2(4-5)2-1), start by evaluating (4-5), which equals -1.
- Multiply -2 by -1 to get 2.
- The expression becomes 3(2+3-22-1) - ...
2. Continue simplifying:
- Inside the second set of parentheses, (2+3-22-1), evaluate the subtraction first: 2-2=0.
- Now the expression becomes 3(2+3-2(0)-1) - ...
3. Simplify further:
- Inside the second set of parentheses, 2(0), equals 0.
- The expression becomes 3(2+3-0-1) - ...
4. Simplify the remaining operations:
- Inside the first set of parentheses, (2+3-0-1), evaluate the addition and subtraction:
2 + 3 - 0 - 1 = 4.
- The expression becomes 3(4) - ...
5. Simplify the multiplication:
- Multiply 3 by 4: 3 * 4 = 12.
- The expression becomes 12 - ...
6. Continue simplifying the rest of the expression:
- Now we have: 12 - (3(2 + 4(4-2)-8+3(2-5)+1-2)1-3) + 4 - 5.
Note: Since there are discrepancies and missing operators towards the end of the expression, it's challenging to provide a definite solution without further clarification or correction.