Help please I'm stuck in this 3 problems.
1.Find the center and radius of the circle (x - 1)2 + y2 = 36
2.Find the distance between the two points. Round an approximate result to the nearest hundredth(8, 0) and (0, 6)
3.Give the equation of the line that is perpendicular to the line y = x + 4 and passes through point(0,-1)
1. if (x-h)^2 + (y-k)^2 = r^2 , then the centre is (h,k) and the radius is r
thinking of your equation as
(x-1)^2 + (y-0)^2 = 6^2 ,
can you state the centre and radius ?
2. For any two points (a,b) and (c,d) the distance between them is given by
√[(a-c)^2 + (b-d)^2]
use this formula and evaluate for your two points.
3. The slope of the given line is 1 , using the pattern of y = mx + b
since perpendicular lines have slopes that are opposite reciprocals of each other, the new slope must be -1
so the new equation is
y = -x + b
but (0,-1) is the y-intercept or the b of the equation, so the new equation is
y = -x - 1