I don't know how to start this problem and it goes like this 6y2 = 7y - 5?
Can you please help me just to start it off
multiply 6 and 2, so it would be 12y=7y-5
ok so can you check my work if I did it correct
12y-7y-5=0
5y-5=0
y=1
It would be -1.
12y=7y-5
then you subtract 7y and you get:
5y=-5
then you divide 5 for both sides so you get:
y=-1
look at the end of
http://www.jiskha.com/display.cgi?id=1252204085
wait, then is the 2 supposed to be an exponent?
Yes i'm sorry for the misunderstanding
Of course! I can help you get started with this problem.
To begin, let's rearrange the equation so that all the terms are on one side.
The equation is: 6y^2 = 7y - 5.
To move all the terms to one side, we need to subtract 7y and add 5 to both sides of the equation. This gives us:
6y^2 - 7y + 5 = 0.
Now, we have a quadratic equation in the form of ax^2 + bx + c = 0, where a = 6, b = -7, and c = 5.
To solve this quadratic equation, you can use methods such as factoring, completing the square, or using the quadratic formula. Which method would you like to use?