1/3x > 2 and 1/4x > 2

both are less than one so how do i graph this on the number line?

I'm confused.

I will assume you meant (1/3)x>2 and not 1/(3x)>2

With that assumption, you would get x>6 AND x>8

x>6 is a line to the right of 6, excluding the 6
x>8 is a line to the right of 8, excluding the 8

So the intersection, or all elements that belong to BOTH, would be all those to the right of 8, exluding the 8, since 8 satisfies the first but not the second

so draw on open circle around the 8 then a line to the right of it, with an arrow at its end

How do you graph 1/4x-5

To graph the inequalities (1/3)x > 2 and (1/4)x > 2 on a number line, you can follow these steps:

1. Simplify the inequalities:
- Multiplying both sides of the first inequality by 3, you get x > 6.
- Multiplying both sides of the second inequality by 4, you get x > 8.

2. Draw a number line with the smallest relevant number on the left and the largest relevant number on the right. Since both inequalities state that x is greater than a certain number, we start from the right side of the number line.

3. Locate the number 8 on the number line. As x > 8, we represent 8 with an open circle because it does not satisfy the second inequality (1/4)x > 2.

4. Draw an arrow starting from the open circle towards the right side of the number line, indicating that all values greater than 8 satisfy both inequalities.

The resulting graph on the number line should have an open circle around 8 and an arrow pointing to the right. This represents all values of x greater than 8 that satisfy both (1/3)x > 2 and (1/4)x > 2.