Write a quadratic equation in the variable x having the given numbers as solutions. Type the equation in standard form ax^2 + bx + c =0
The solutions are -10, 3
The equation is blank = 0
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This question is algebra
To find a quadratic equation with the given solutions of -10 and 3, we can use the fact that the solutions of a quadratic equation ax^2 + bx + c = 0 are given by the roots of the equation.
In this case, the solutions are -10 and 3. To incorporate these solutions into the equation, we can set up two separate equations as follows:
(x - (-10)) = 0 --> (x + 10) = 0
(x - 3) = 0
Now, we can multiply the two equations together to get a quadratic equation.
(x + 10)(x - 3) = 0
Expanding this equation gives:
x^2 - 3x + 10x - 30 = 0
x^2 + 7x - 30 = 0
Therefore, the quadratic equation in standard form with the solutions -10 and 3 is:
x^2 + 7x - 30 = 0