chemistry

what is the molarity of the solution which contains 5.0g of NaOH(formar weight=40g/mole)dissolved in water to make 200 ml of soluitons?

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asked by DJ
  1. moles = grams/molar mass
    molarity = mols/L
    Post your work if you get stuck.

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    posted by DrBob222
  2. m=mols/L

    first, get the no. of moles.
    n=wt/mw
    where n = no. of moles
    wt = weight
    mw = molecular weigth

    n = 5.0g / 40 g/mol
    cancel the grams, so the left unit is mol.
    Ans. n=0.125mol

    You can now get the molarity of the solution,

    m = n/L
    where m = molarity
    m= 0.125mol / 200ml
    *conversion:
    1L=1000ml
    200ml x 1L/1000mL
    ==> 0.2L

    you can now solve the molarity
    m= 0.125mol / 0.2L
    ANS: m = 0.625mol/L

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