Solve the equation algebraically for x where 0 </ x <2pi.
sin x = sqrt(3) cos x
divide both sides by cosx to get
tanx = √3
knowing your 30-60-90 triangle, you know that tan 60º = √3
but the tangent is also positive in quadrant III or tan 240º = √3
so in degrees, the solution is 60º, 240º
in radians pi/3, 4pi/3