A bank teller has some five-dollar bills and some twenty-dollar bills. The teller has 10 more of the
twenties. The total value of the money is $850. Find the number of five-dollar bills that the teller
has?
N*20 + (N-10)10=850
check that.
Thanks that was all that I needed now let me work on my problem and tell if I got the correct answer.
N*20+(N-10)10=850
20n+20n-200+10=850
40n-190=850
n=26
That works out correctly.
26 * $5 = #130
36 * $20 = $720
130 + 720 = 850
Who killed
To solve this problem, we need to set up a system of equations. Let's represent the number of five-dollar bills as "x" and the number of twenty-dollar bills as "y".
From the problem, we know that the teller has 10 more twenties. So, we can write the equation:
y = x + 10
The total value of the money is $850. Since each five-dollar bill is worth $5 and each twenty-dollar bill is worth $20, we can write the second equation:
5x + 20y = 850
Now we have a system of two equations:
y = x + 10 (Equation 1)
5x + 20y = 850 (Equation 2)
We can solve this system of equations to find the values of x and y.
First, substitute the value of y from Equation 1 into Equation 2:
5x + 20(x + 10) = 850
Simplify the equation:
5x + 20x + 200 = 850
Combine like terms:
25x + 200 = 850
Subtract 200 from both sides:
25x = 650
Divide both sides by 25:
x = 26
Therefore, the bank teller has 26 five-dollar bills.