Please Help, Physics

A runner dashes from the starting line (x = 0) to a point 130 m away and then turns around and runs to a point 11 m away from the starting point in 21 seconds. To the nearest tenth of a m/s what is the average speed?
What is the runner's average velocity in the previous problem?

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  1. 1. average speed
    Total distance
    = 130 + 130 - 11
    = 249 m
    Total time = 21 s.
    Average speed
    = total distance / total time
    =?? m/s

    2. average velocity
    Total displacement
    = 11
    Total time
    = 21 s.
    Average velocity = total displacement/total time
    = ?? m/s

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  2. avg velocity=changedisplacement/time=11m/21s

    avg speed=changedistance/time=(130+130-11)/21 m/s

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