9+(P+3) P=?
What do you want done with this?
how do I solve 9+(P+3)
Your first post is not the same as the response to my question.
I will assume the first one is correct.
9+(P+3)P=?
Clear the parentheses and multiply by P.
9 + P^2 + 3P = 0 (I guess this is zero although you didn't say what it was equal to). Now rearrange to
P^2 + 3P + 9 = 0
I would use the quadratic formula.
To find the value of P in the expression 9 + (P + 3), we need to isolate P.
First, let's simplify the expression by combining like terms. Within the parentheses, P and 3 are the only variables, so we can simplify P + 3 to get 9 + P + 3.
Now, let's combine the numerical terms by adding 9 and 3, which gives us 12 + P.
The expression can now be written as 12 + P.
Since we're looking for the value of P, we can isolate it by subtracting 12 from both sides of the equation.
12 + P - 12 = 0 + P
On the left side, 12 and -12 cancel each other out, leaving us with just P.
P = 0 + P
Therefore, the value of P is equal to 0.