How many moles of iodine are produced from 7.00 moles of chlorine, according to the equation shown?
3Cl2(g) + 2FeI2(s) --> 2FeCl3(s) + 2I2(g)
4.67
7 moles Cl2 x (2 moles I2/3 moles Cl2) = 4.67.
To determine the number of moles of iodine produced, you need to use the stoichiometry of the balanced chemical equation. The coefficients in the equation represent the molar ratios between the reactants and products.
From the balanced equation:
3Cl2(g) + 2FeI2(s) --> 2FeCl3(s) + 2I2(g)
The ratio between Cl2 and I2 is 3:2. This means that for every 3 moles of Cl2, 2 moles of I2 will be produced.
Therefore, if you have 7.00 moles of Cl2, you can use a proportion to find the moles of I2:
(2 moles I2 / 3 moles Cl2) x 7.00 moles Cl2 = 4.67 moles I2
Therefore, 7.00 moles of chlorine will produce 4.67 moles of iodine according to the balanced equation.