a ball dropped from a cliff falls with a constant acceleration of 10m/s*s . through how much distance the ball will fall in the 5th second
50 meters. ... 10x5
distanceat end of fourth second= 1/2 g (4)^2
distanceatendofFifth second= 1/2 g 5^2
distancein fifth second= 1/2 g (25-16)
To find the distance the ball will fall in the 5th second, we can use the kinematic equation for distance:
d = ut + (1/2)at^2
Where:
d = distance
u = initial velocity (zero in this case as the ball is dropped)
a = acceleration (10 m/s^2)
t = time (5 seconds)
Substituting the values into the equation:
d = 0(5) + (1/2)(10)(5^2)
d = 0 + (1/2)(10)(25)
d = 0 + 5(25)
d = 0 + 125
d = 125 meters
Therefore, the ball will fall a distance of 125 meters in the 5th second.