In a netball competition, there are 9 teams. If each team plays each other twice, what is the total number of games played?
The first round would be 9choose2 games,
which is 9!/(7!2!) = 36
But you are playing two rounds, so the total number of games is 72
To find the total number of games played in a netball competition with 9 teams, where each team plays each other twice, you can use the combination formula.
First, you need to calculate the number of games played in the first round. In the first round, each team will play against all the other teams once. So, you need to find the number of combinations of 9 teams taken 2 at a time. This is denoted as "9 choose 2" and can be calculated using the formula:
9! / (7! * 2!) = 36
Next, since each team plays each other twice, you need to multiply the number of games in the first round by 2 (for the second round).
So, the total number of games played in the netball competition would be:
36 * 2 = 72 games.