A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. how much did the hockey puck accelerat?
see the post above
x-components =(3.10)(cos25.0)=2.81
y-components=(3.10)(sin25.0)=1.31
To calculate the acceleration of the hockey puck, we can use the formula for acceleration:
acceleration (a) = change in velocity (Δv) / time (Δt)
In this case, the change in velocity (Δv) is given as 6 m/s, and the time (Δt) is given as 2 seconds.
Substituting these values into the formula:
acceleration (a) = 6 m/s / 2 s
Simplifying the equation:
acceleration (a) = 3 m/s²
Therefore, the hockey puck accelerated at a rate of 3 m/s².