Find the distance of the line segment whose endpoints are (5,7) and (-2,3) in simplest radical form.
sqrt [(7-3)^2 + (5 -(-2))^2]
= sqrt [16 + 49]
= sqrt 65
That is the simplest form I can think of. sqrt means "square root of"
That's correct! The distance of the line segment with endpoints (5,7) and (-2,3) is √65 in simplest radical form.
To find the distance of a line segment whose endpoints are (5,7) and (-2,3) in simplest radical form, you can use the distance formula in the coordinate plane.
The distance formula is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case,
x1 = 5, y1 = 7
x2 = -2, y2 = 3
Plugging these values into the formula, we get:
d = sqrt((-2 - 5)^2 + (3 - 7)^2)
Now, let's simplify this expression:
d = sqrt((-7)^2 + (-4)^2)
= sqrt(49 + 16)
= sqrt(65)
So, the distance of the line segment is sqrt(65) in simplest radical form.