What is the volume in cubic cm of a sphere with radius 2 cm?
is it =
33.51032163829112
What is the area in m2 of a triangle with base 2.8 m and height of 10.4 m?
is it =
14.56
A sphere has a volume of 106 cm3. What is its radius (in cm)?
is it =
101.8112097952136
that doesnt look right :/
yes. Unless you have to worry about significant digits.
yes, but I wonder if you should be paying attention to sig digits.
No.
radius=cuberoot (3*volume/(4PI))
The first two are OK. For the third question, use
R^3 = [3/(4 pi)]*V
and then take the cube root
To get cube root on a calculator, use the yx key
as
NUMBER yx (1/3) =
That give you the cube root of NUMBER
Yes, I do have to be paying attention to sig figs, just for this chapter though
and for the third one, is it 6.297560287884612?
To find the volume of a sphere with a given radius, you can use the formula:
Volume = (4/3) * pi * radius^3
For the first question, the volume of a sphere with a radius of 2 cm can be calculated as:
Volume = (4/3) * pi * (2 cm)^3
= (4/3) * 3.14159 * 8 cm^3
= 33.51032163829112 cm^3
So, your answer is correct.
For the second question, the area of a triangle can be found using the formula:
Area = (1/2) * base * height
Therefore, for a triangle with a base of 2.8 m and a height of 10.4 m, you can calculate the area as:
Area = (1/2) * 2.8 m * 10.4 m
= 14.56 m^2
Again, your answer is correct.
For the third question, to find the radius of a sphere with a given volume, you need to rearrange the volume formula:
Volume = (4/3) * pi * radius^3
By dividing both sides by (4/3) * pi, you get:
Radius^3 = Volume / ((4/3) * pi)
And then take the cube root of both sides:
Radius = (Volume / ((4/3) * pi))^(1/3)
Using this formula, for a sphere with a volume of 106 cm^3, you can calculate the radius as:
Radius = (106 cm^3 / ((4/3) * 3.14159))^(1/3)
= (106 cm^3 / 4.18879)^(1/3)
= 4.880792585482143 cm
So, the radius of the sphere is approximately 4.88 cm, not 101.8112097952136 cm. It seems there was an error in your calculation.
Please let me know if you need further assistance or clarification!